The best way to find a cheap fare is to book your ticket as far in advance as you can and to avoid traveling at rush hour.
This is the last train of the day.
Find all the dates and times for this journey
1 h 34 m
9 h 36 m
Trains per day
It's difficult to get from Bloomington, IL to Tinley Park, IL without transferring at least once.
|Distance||97 miles (157 km)|
|Average train duration||1 h 30 min|
|Average train ticket price||$19 (€17)|
|Train frequency||2 a day|
Trains from Bloomington, IL to Tinley Park, IL cover the 97 miles (157 km) long trip taking on average 1 h 30 min with our travel partners like Amtrak. Normally, there are 2 trains operating per day, including direct services available. While the average ticket price for this journey costs around $19 (€17), you can find the cheapest train ticket for as low as $19 (€17).
Travel to Tinley Park, IL from Bloomington, IL from $19 (€17) with Omio’s train partners Amtrak! You can find the best schedules and tickets when comparing and booking the most affordable route for you.
Amtrak is the main train company in the United States operating medium and long-distance intercity services in 46 US states as well as in 3 Canadian provinces. There are over 300 Amtrak trains running daily. With Amtrak you can travel by train across the country and explore destinations near and far with routes such as the Northeast Regional connecting cities in the East Coast, the Coast Starlight connecting destinations up and down the West Coast, the Empire Builder connecting Chicago and Midwestern cities to the Northwest, and many more. Amtrak offers different class options suiting any budget, from Coach Class to Business Class, First Class, and the Sleeper Class, where you can book a Roomette, Bedroom, and Bedroom suite among others for night travel. There are several different ticket types including Saver, Value, Flexible, Business and Premium for you to book for your next train journey from Bloomington, IL to Tinley Park, IL.
Train information from Bloomington, IL to Tinley Park, IL with Amtrak:
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